This question was previously asked in

UPPCL AE EC 2019 Official Paper (Held On 5 November 2019)

Option 3 : -275

CT 3: Building Materials

3014

10 Questions
20 Marks
12 Mins

__Concept__:

The difference mode gain (A_{v}) for BJT differential Amplifier is given as:

\({A_v} = - \frac{1}{2} \times \frac{{{h_{fe}} \times {R_c}}}{{{h_{ie}}}}\)

__Calculation__**:**

With h_{fe} = 200, R_{c} = 3.3 kΩ, and h_{ie} = 1.2 kΩ, we get:

\({A_v} = - \frac{1}{2} \times \frac{{{h_{fe}} \times {R_c}}}{{{h_{ie}}}}\)

\({A_v} = - \frac{1}{2} \times \frac{{200 \times 3.3 \times {{10}^3}}}{{1.2 \times {{10}^3}}}\)

A