\(\dfrac{22}{3}, \dfrac{20}{5}, \dfrac{18}{7}, ?, \dfrac{14}{11}\)

In this series question mark can be substituted by

This question was previously asked in

DSSSB JE E&M 2014 Official Paper (Held on 28 Dec 2014)

- \(\dfrac{15}{8}\)
- \(\dfrac{16}{7}\)
- \(\dfrac{15}{9}\)
- \(\dfrac{16}{9}\)

Option 4 : \(\dfrac{16}{9}\)

Free

CT 1: Indian History

18450

10 Questions
10 Marks
6 Mins

The pattern follows here is;

1) Numerator is decreased by 2.

3) Denominator is increased by 2.

So, the Missing term of the series is \(\dfrac{16}{9}\).

Hence, **option (4) **is the correct answer.

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